The three people who get this LOVE IT.

Not quite, 15 year old. That is e^(i*pi) not e^(2pi). As in the imaginary number.
0.002 + e^(i*pi) + SUM[1/(2^n) = 0.002
0.002 + (1) + 1 = 0.002

This is what happens when an engineer get's pissed at his bills

There's a high probability that someone wont be able to solve the problem correctly, and a high probability that you're going to be overcharged. Smart ass.

I'll show verizon, I'll take 30 min. and write them a check.

lol did anyone notice the date?

e to the i pi = 1
infinite sum from n=1 of 1/(2^n) = 1
So its a cheque for $0.002 ... Im sure he meant $0.02 though  as in his 2 cents (MATHFAIL on the easy bit if that was the case ... lol)

Brain cell Overload !!!

idontgetit

Aw **** he forgot to divide by zero

nice one. MUNROEa

He put the equation in the wrong place.......otherwise wonderful.

That's actually a pretty expensive bill damn...
