| Rate This Image | 3.9 by 43 huffers |
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The three people who get this LOVE IT.
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Not quite, 15 year old. That is e^(i*pi) not e^(2pi). As in the imaginary number.
0.002 + e^(i*pi) + SUM[1/(2^n) = 0.002
0.002 + (-1) + 1 = 0.002
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This is what happens when an engineer get's pissed at his bills
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I'll show verizon, I'll take 30 min. and write them a check.
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e to the i pi = -1
infinite sum from n=1 of 1/(2^n) = 1
So its a cheque for $0.002 ... Im sure he meant $0.02 though - as in his 2 cents (MATHFAIL on the easy bit if that was the case ... lol)
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There's a high probability that someone wont be able to solve the problem correctly, and a high probability that you're going to be overcharged. Smart ass.
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Brain cell Overload !!!
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idontgetit
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nice one. MUNROEa
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Aw **** he forgot to divide by zero
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He put the equation in the wrong place.......otherwise wonderful.
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Mathematical question :P n goes to infinity so (2^n) goes to infinity so (1/2^n) is (1/inf.) so it's zero, right? it can't be 1!
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That's actually a pretty expensive bill damn...
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